Time: 39 ms (41.13%) | Memory: 16.5 MB (66.24%) - LeetSync

Author: aviiciii

19-remove-nth-node-from-end-of-list/remove-nth-node-from-end-of-list.py

@@ -0,0 +1,33 @@
+# Definition for singly-linked list.
+# class ListNode:
+#     def __init__(self, val=0, next=None):
+#         self.val = val
+#         self.next = next
+class Solution:
+ def removeNthFromEnd(self, head: Optional[ListNode], n: int) -> Optional[ListNode]:
+ if not head:
+ return None
+ if not head.next:
+ return None
+
+
+ fast = head
+ 
+ for i in range(n):
+ fast= fast.next
+ if not fast:
+ return head.next
+
+ slow = head
+ if fast:
+ while fast.next != None:
+ slow = slow.next
+ fast = fast.next
+ 
+ slow.next = slow.next.next
+
+
+ # prev.next = temp.next
+ return head
+
+